Heating/Cooling Curves
In thermochemistry, the relation between the amount of heat absorbed or released by a substance, q, and its accompanying temperature change, ΔT, was introduced:
q=mcΔT
where m is the mass of the substance and c is its specific heat. This relation, however, applies to matter being heated or cooled, but not undergoing a change in state.
When a substance being heated or cooled reaches a temperature corresponding to one of its phase transitions, further gain or loss of heat is a result of diminishing or enhancing intermolecular attractions, instead of increasing or decreasing molecular kinetic energies. While a substance is undergoing a change in state, its temperature remains constant.
The amount of heat required to change one mole of a substance from the liquid state to the gas state is the enthalpy of vaporization, ΔHvap. For example, the vaporization of water at standard temperature is represented by:
H2O(l)⟶H2O(g) ΔHvap=44.01 kJ/mol
The amount of heat required to change one mole of a substance from the solid state to the liquid state is the enthalpy of fusion, ΔHfus of the substance. The enthalpy of fusion of ice is 6.0 kJ/mol at 0 °C. Fusion (melting) is an endothermic process:
H2O(s)⟶H2O(l) ΔHfus=6.01 kJ/mol
A typical heating curve for a substance depicts changes in temperature that result as the substance absorbs increasing amounts of heat. Plateaus in the curve (regions of constant temperature) are exhibited when the substance undergoes phase transitions. A cooling curve is the reverse of the heating curve. A cooling curve depictschanges in temperature that result as the substance releases increasing amounts of heat.
In summary, the heat needed to change the temperature of a given substance (the slanted region of a heating/cooling curve) is:
q = m × c × ΔT (no phase transitions)
The heat needed to induce a given change in phase (the plateaus region of the heating/cooling curve) is given by
q = n × ΔH (no temperature changed)
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In this lab, you will observe the phase changes of water and draw heating and cooling curves of water with a computer simulation.
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https://interactives.ck12.org/simulations/chemistry/phases-of-matter/app/index.html?screen=sandbox
You will see this on your screen.
Part I Heating Curve
Select the starting state to be Solid and the final state to be Gas, start the heating by clicking the arrow on the lower left. Observe the molecular change happens within the cup and pay attention to the heating curve on the upper left and the temperature shown on the upper right. Answer questions asked on the Data Sheet.
Part II Cooling Curve
Select the starting state to be Gas and the final state to be Solid, start the cooling by clicking the arrow on the lower left. Observe the molecular change happens within the cup and pay attention to the cooling curve on the upper left and the temperature shown on the upper right. Answer questions asked on the Data Sheet.
Part I Heating Curve
Part II Cooling Curve
cliquid water = 4.184 J/g °C
csteam= 1.84 J/g °C
cice= 2.09 J/g °C
ΔHvap = 40.65 kJ/mol
ΔHfus = 6.01 kJ/mo
cliquid water = 4.184 J/g °C
csteam= 1.84 J/g °C
cice= 2.09 J/g °C
ΔHvap = 40.67 kJ/mol at 36.6 °C.
ΔHfus = 6.01 kJ/mol
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